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3 years ago

Help please 11 minutes

Mathematics

2 answers:

bazaltina [42]3 years ago

7 0

The value of X is 6

reduce the numbers 6x2/3x=24

calculate the product 2x2x=24

divide both sides by 4 4x=24

x=6

Papessa [141]3 years ago

7 0

The answer is 6. You divide the 6 on both sides. Then you multiply by the reciprocal of 2/3 on both sides to get x alone.

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What is 2/7 divided by 6

Lorico [155]

Question

What is 2/7 divided by 6

Answer:

Step-by-step explanation:

2/7 : 6 =

2/7 * 1/6 =

1/21

8 0

3 years ago

REPLY ASAP PLEASE!!!

d1i1m1o1n [39]

Answer:

The answer is c.

Step-by-step explanation:

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3 years ago

F(x) = 2x – 1 g(x) = 7x – 12 What is h(x) = f(x) + g(x)?

WINSTONCH [101]

Answer:

Solution,

 $h(x) = f(x) + g(x) \\ \: \: \: \: \: \: \: = 2x - 1 + 7x - 12 \\ \: \: \: \: \: \: = 2x + 7x - 1 - 12 \\ \: \: \: \: \: \: = 9x - 13$ 

hope this helps...

Good luck on your assignment..

4 0

3 years ago

Read 2 more answers

Jordan is buying plastic plates for a party.The plates usually cost $2.40 per 10 plates,but they are on sale for 30% off usual p

Tom [10]

30% off means they are paying 70% of the original price.

Sale price = 2.40 x 0.70 = $1.68 for 10 plates

50 plates / 10 = 5

They buy 5 packages of plates.

1.68 x 5 = $8.40

Total price = $8.40

6 0

3 years ago

Read 2 more answers

A test of sobriety involves measuring the subject's motor skills. Twenty randomly selected sober subjects take the test and prod

elena55 [62]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: motor skills of a sober subject.

n= 20

X[bar]= 37.1

S= 3.7

The claim is that the average score for all sober subjects is equal to 35.0, symbolically: μ= 35.0

The hypotheses are:

H₀: μ = 35.0

H₁: μ ≠ 35.0

α: 0.01

The statistic to use, assuming all conditions are met, is a one sample t- test

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

$t_{H_0}= \frac{37.1-35.0}{\frac{3.7}{\sqrt{20} } } = 2.34$

This test is two-tailed, meaning, the rejection region is divided in two and you'll reject the null hypothesis to low values of t or to high values of t:

$t_{n-1;\alpha /2}= t_{19; 0.005}=-2.861$

$t_{n-1;1-\alpha /2}= t_{19; 0.995}= 2.861$

The decision rule using this approach is:

If $t_{H_0}$ ≤ -2.861 or if $t_{H_0}$ ≥ 2.861, you reject the null hypothesis.

If -2.861 < $t_{H_0}$ < 2.861, you do not reject the null hypothesis.

The value is within the non rejection region, the decision is to not reject the null hypothesis.

I hope this helps!

3 0

3 years ago