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vladimir2022 [97]
3 years ago
9

Expression 9(2j + 7 + 5j).

Mathematics
2 answers:
Feliz [49]3 years ago
6 0

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Allisa [31]3 years ago
3 0
9(2j+7+5j)
9(7j+7)
63j+63
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At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. The di
lawyer [7]

Answer:

0.0063 ft / min

Step-by-step explanation:

From the problem statement we have that the variation in volume with respect to time is equal 10, like this:

dV / dt = 10 ft ^ 3 / min

We know that the volume of the cone is given by the equation:

V = (1/3) * Pi * r ^ 2 * h

Now, we are mentioned that the diameter of the base of the cone is approximately three times the altitude, therefore:

2r = 3h, solving for r we have:

r = (3/2) * h, replacing the volume equation:

V = (1/3) * Pi * [(3h / 2) ^ 2] * h, solving we have:

V = (3/4) * Pi * h ^ 3

They ask us to calculate the change in height with respect to time, that is dh / dt

Therefore we derive both sides with respect to time, we have to:

dV / dt = (3/4) * Pi [3 * (h ^ 2) dh / dt] = (9/4) * pi * (h ^ 2) * dh / dt

reorganizing for dh / dt, we have:

dh / dt = [4/9 * pi * (h ^ 2)] * dV / dt

Knowing that h is 15 and dV / dt is 10, we replace these values:

dh / dt = [4/9 * 3.14 * (15 ^ 2)] * 10 = 0.0063 ft / min

0.0063 ft / min would be the change in height with respect to time.

4 0
3 years ago
6/13 by 6/12? what is the answer
Leto [7]
(6/13)/(6/12)= (6/13)*(12/6)= 12/13   
This rule for division applies to all fraction divisions

4 0
3 years ago
Read 2 more answers
Need help with number 1 and 2!
Musya8 [376]

Answer:

Step by step explanation:

1.PY=LA

2.NO=OS.

4 0
3 years ago
Given sec(theta)= 5... find cot(90-theta)
Mumz [18]
\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 }  = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6}  
\\

3 0
3 years ago
H(-3), h(5), h(2), h(0)
romanna [79]

Answer:

h(-3) = -3h

h(5) = 5h

h(2) = 2h

h(0) = 0

5 0
2 years ago
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