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-BARSIC- [3]
3 years ago
11

Simplify: (a4 - 6a + 5) - (a4 - 3a + 2a2 - 6)

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
(a4-6a+5)-(a4-3a+4a-6)
by expressing like term
a4-a4=0
-6a-(-3a+4a)=-5a
5-(-6)=11
:we have-5a+11
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Inverse Operation of Multiplication.
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Which equation represents a line that passes through (2, -1/2) and has a slope of 3?
Anastasy [175]

Answer:

Equation of line is:

y=3x-\dfrac{13}{2}

Step-by-step explanation:

Let equation of line be y=mx+c

where m is the slope of line and c is the y-intercept

Line passes through (2, -1/2) and has a slope of 3

i.e. (x,y)=(2, -1/2) and m=3

i.e.

-\dfrac{1}{2}=3\times 2+c\\ \\c= -\dfrac{1}{2}-6\\ \\c= -\dfrac{13}{2}

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y=3x-\dfrac{13}{2}

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Write 3.005 as a fraction in the simplest form​
liberstina [14]

Answer: 601

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Find the area of a square with side length 3/4 yard
Roman55 [17]

The area of square with side of 3/4 yards is 9/16 square yards

Step-by-step explanation:

The formula for area of square is given by:

Area = s^2

where s is the side of the square

Given

Side of square = s = 3/4 yards

So,

Area = s^2\\= (\frac{3}{4})^2\\=\frac{9}{16}

Hence,

The area of square with side of 3/4 yards is 9/16 square yards

Keywords: Area of square, side

Learn more about area of square at:

  • brainly.com/question/1608863
  • brainly.com/question/13239838

#LearnwithBrainly

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4 years ago
The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3
Alekssandra [29.7K]

Answer:

9\pi \text{ cubic meters per hour}

Step-by-step explanation:

Since, the surface area of a cylinder,

A= 2\pi r^2 + 2\pi rh  ................(1)

Where,

r = radius,

h = height,

If A= 36\pi\text{ square meters}, h = 3\text{ meters}

36\pi = 2\pi r^2 + 2\pi r(3)

18 = r^2 + 3r

\implies r^2 + 3r - 18=0

r^2 + 6r - 3r - 18 = 0     ( by middle term splitting )

r(r+6)-3(r+6)=0

(r-3)(r+6)=0

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})

∵ h = constant, ⇒ dh/dt = 0,

\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}

We have, \frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}

9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}

9\pi = (12\pi + 6\pi )\frac{dr}{dt}

9\pi = 18\pi \frac{dr}{dt}

\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}

Now,

Volume of a cylinder,

V=\pi r^2 h

Differentiating w. r. t. t,

\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}

6 0
3 years ago
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