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2 years ago

Simplify: (a4 - 6a + 5) - (a4 - 3a + 2a2 - 6)

Mathematics

1 answer:

Galina-37 [17]2 years ago

7 0

(a4-6a+5)-(a4-3a+4a-6)
by expressing like term
a4-a4=0
-6a-(-3a+4a)=-5a
5-(-6)=11
:we have-5a+11

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The balance in a savings account at the end of each year is shown below. The year is denoted by n, and the account balance is

vovangra [49]

Answer:

A(n) = 100(1.1)^n

Step-by-step explanation:

Given that :

Account balance = A(n)

Compound interest paid = 10%

We need to obtain the initial amount deposited, that is A(n), when n = 0

In year, n = 1

Account balance, A(n) = $110

Let initial deposit = P

Hence,

Compound interest relation should be ;

A(n) = P(1 + r)^n

Plugging in our values

110 = P(1 + 0.1)^1

110 / P = 1.1^1

110/P = 1.1

110 = 1.1P

P = 110 / 1.1

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Hence, we can define the amount paid inn n years by substuting the value of P into the compound interest formula :

A(n) = 100(1 + 0.1)^n

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3 years ago

The function f(x)=(x-1)^2+5 is not one-to-one

Maurinko [17]

Answer:

True

Step-by-step explanation:

If x = 2 Than (x-1)^2 = 1

If x= 0 than (x-1)^2 = 1

For a one to one function this cannot happen as there x determines f(x) but also f(x) determines x.

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3 years ago

If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geomet

morpeh [17]

Answer:

The probability is 0.0428

Step-by-step explanation:

First, let's remember that the binomial distribution is given by the formula:

$P(X=k) =\left[\begin{array}{ccc}n\\k\end{array}\right] p^{k}(1-p)^{n-k}$ where k is the number of successes in n trials and p is the probability of success.

However, the problem tells us that when there isn't a number of trials fixed, we can use the geometric distribution and the formula for getting the first success on the xth trial becomes:

$P(X=x) = p(1-p)^{x-1}\\$

The problem asks us to find the probability of the first success on the 4th trial (given that the first subject to be a universal blood donor will be the fourth person selected)

Using this formula with the parameters given, we have:

p = 0.05

x = 4

Substituting these parameters in the formula and solving it, we get:

$P(X=4) = 0.05(1-0.05)^{4-1}\\P(X=4) = 0.05 (0.95)^{3}\\P(X=4) = 0.05(.8573)\\P(X=4) = 0.0428$