Check the attached file for the solution.
If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:
k / 2 + 9 = 30
k / 2 = 30 - 9
k / 2 = 21 /*2
k = 21 * 2
k = 42
The result is 42.
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
Step-by-step explanation:
2x³+4x²-x, first find the Greatest Common Factor (GCF), which is x. To find the GCF, look at what all the numbers have in common, and then see if it has the greatest value. Next factor out the GCF.
Simplify each term in the parentheses.
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! :-)
- Cutiepatutie ☺❀❤
I believe the possible volumes are <span>5 ft long, 4 ft wide and 2 ft deep
5 ft long, 3 ft wide and 2 ft deep
5 ft long 2 ft wide and 2 ft deep
5 ft long, 1 ft wide and 2 ft deep</span>