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Levart [38]
3 years ago
8

Which equation represents a line that passes through (2, -1/2) and has a slope of 3?

Mathematics
2 answers:
Anastasy [175]3 years ago
8 0

Answer:

Equation of line is:

y=3x-\dfrac{13}{2}

Step-by-step explanation:

Let equation of line be y=mx+c

where m is the slope of line and c is the y-intercept

Line passes through (2, -1/2) and has a slope of 3

i.e. (x,y)=(2, -1/2) and m=3

i.e.

-\dfrac{1}{2}=3\times 2+c\\ \\c= -\dfrac{1}{2}-6\\ \\c= -\dfrac{13}{2}

So, equation of line is:

y=3x-\dfrac{13}{2}

stealth61 [152]3 years ago
3 0

We can use the point-slope from of a line to find this equation. The general equation is:

y-y_{1}=m(x-x_{1}

So then, if the subscripted letters are respective to the point (2, -1/2), and m is equal to the slope (3) then we can put together the equation:

y-(-\frac{1}{2} )=3(x-2)

Then we can simplify:

y+\frac{1}{2}  =3x-6

y=3x+5\frac{1}{2} or y=3x+\frac{11}{2}

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n the graph below determine how many real solutions the quadratic function has, and state them, if applicable. List solutions in
IRINA_888 [86]

Answer:

There are no real solutions.

Step-by-step explanation:

There are 3 options.

2 real solutions: This happens if in the graph, each arm intersects the x-axis, this means that there are two different values of x such that the equation:

a*x^2 + b*x + c

is equal to zero.

Another way to see this, is if the determinant:

b^2 - 4*a*c

is larger than zero.

1 real solution: This happens when the vertex of the graph intersects the x-axis. This means that there is a single value of x such that:

a*x^2 + b*x + c

is equal to zero.

Another way to see this is if the determinant:

b^2 - 4*a*c

is larger equal zero.

No real solution: if in the graph we can not see any intersection of the x-axis, then we do not have real solutions (only complex ones).

Another way to see this is if the determinant:

b^2 - 4*a*c

is smaller than zero.

Now that we know this, let's look at the graph.

We can see that the vertex is below the x-axis, and the arms of the graph go downwards. So the arms will never intersect the x-axis (and neither the vertex).

So the graph does not intersect the x-axis at any point, which means that there are no real solutions for the quadratic equation.

The correct answer would be "none"

3 0
3 years ago
How many shirts were sold for 13 or more
muminat

Add all the numbers for 13, 14 , 15 and 16 which is 6+4 +0 +2 = 12

so 12 shirts

and one sock with pink toes

6 0
3 years ago
What is the value of n?<br><br> Enter your answer in the box.<br><br> n = <br> cm
dmitriy555 [2]
If two chords intersect each other inside a circle, the products of their segments are equal.

3n = 6*4
3n = 24
n = 24/3
n = 8
6 0
3 years ago
Read 2 more answers
Find the length of the missing side. Simplify the radical if necessary
Phoenix [80]

Answer:

26

Step-by-step explanation:

24²+10²=x²

676=x²

x=√676

x=26

Pythagorean theorem

4 0
3 years ago
This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
3 years ago
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