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attashe74 [19]
3 years ago
5

There are 124 students making 3 stars each for the

Mathematics
2 answers:
forsale [732]3 years ago
8 0

Answer:

D

Step-by-step explanation

124 times 3 is 372

stellarik [79]3 years ago
7 0
D. 372| multiply 124 by 3
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0.5 - Y - 5<br> -0.5x = y - 5<br> Х
Artemon [7]

Answer:

1 - 4y

Step-by-step explanation:

0.5 - Y - 5 -0.5x = y - 5

0.5 +5 -5 -0.5x = 2y

0.5 -2y = 0.5x

x = 0.5 - 2y /0.5

= 1 - 4y

6 0
3 years ago
Select all pairs that are solutions
Mashcka [7]

Answer:

the first one and the third and the fourth

Step-by-step explanation:

4 0
3 years ago
I AM OFFERING 50 POINTS FOR THIS ANSWER. PLEASE HELP ME !
likoan [24]

Answer:

question 8: 30975

question 9:

I don't know if it wants me to find the interest from the bond or the quote price of the bond.

If it is the bond it would be $1400 interest.

If it is the quote price of the bond, it would be $1,239 interest.

5 0
4 years ago
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
3 years ago
A card is drawn at random from a pack of 52 playing cards. Given that the card is a diamond, find the probability that the card
lesantik [10]

Answer:

1/52

Step-by-step explanation:

There is only one of each type of card in each suit.

P(card is a diamond) = 13/52

P(card is a diamond + king) = (13/52)×(1/13) = (13/676) = (1/52)

8 0
4 years ago
Read 2 more answers
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