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malfutka [58]
3 years ago
14

Simplify 4^10/4^10×7^0 as much as possible

Mathematics
1 answer:
Aloiza [94]3 years ago
4 0

Answer:

1 is the answer because 4^10=1048576 and you have that on the top and the bottom of the problem then 7^0=1 so therefore 1048576/1048576=1

Step-by-step explanation:

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A square fits exactly inside a circle with each of the vertices being on the circumference of the circle. The square has sides l
NNADVOKAT [17]

Answer: The value of x is 5.970.

Step-by-step explanation:

Given: The square has sides length of X cm.

Let r be the radius of the circle.

The square fits exactly inside a circle with each of the vertices being on the circumference of the circle.

Then diagonal of square = diameter of circle

i.e. \sqrt{2}x= 2r    [Diagonal of square = \sqrt{2}(side)]

i.e. r=\dfrac{x}{\sqrt{2}}

area of circle =\pi r^2

i.e. 56=\frac{22}{7}(\frac{x}{\sqrt{2}})^2

56=\frac{22}{7}\times\frac{x^2}{2}\\\\\Rightarrow\ x^2= \dfrac{7}{11}\times56\\\\\Rightarrow\ x^2=35.636\\\\\Rightarrow\ x=\sqrt{35.636}\approx5.970

Hence, the value of x is 5.970.

4 0
3 years ago
At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive
schepotkina [342]
<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>
3 0
4 years ago
Which situation shows a constant rate of change?
kolbaska11 [484]
The answer is most likely B. :)
3 0
2 years ago
Which of these numbers is irrational?
Sidana [21]
<span>Which of these numbers is irrational?
a. square root of 3
b. 0.25
c. 1/5
d. square root of 9

answer
</span><span>a. square root of 3
</span><span>--------------------------------
What is (-7)^5 in expanded form?
a. -7 • -7 • -7 • -7 • -7 
b. -7 • 5
c. (-7) • 7 • (-7) • 7 • (-7) • -7
d. 5 • 5 • 5 • 5 • 5 • 5 • 5

answer

</span><span>a. -7 • -7 • -7 • -7 • -7 </span>
6 0
3 years ago
The weight of an apple is 150g, rounded to the nearest 5g. what is the lower bound and upper bound?
Aneli [31]

The lower bound is 147.5 and the upper bound is 152.5.

Given the weight of an apple 150 g rounded to the nearest 5g.

We have to find lower bound and upper bound.

Lower bound is an element less than or equal to all the elements in a given set.

Upper bound is an element greater than all the elements in a given set.

Lower bound= Number 1- (Number nearest to  which number 1 is rounded)/2

Upper bound=Number 1+(number nearest to which number 1 is rounded)/2

Weight of an apple =150 g

Lower bound=150-5/2

=150-2.5

=147.5

Upper bound=150+5/2

=150+2.5

=152.5

Hence the lower bound is 147.5 and upper bound is 152.5.

Learn more about lower and upper bounds at brainly.com/question/15408313

#SPJ4

4 0
2 years ago
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