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harkovskaia [24]
3 years ago
10

Using the quadratic formula to solve 4x^2-3x+9=2x+1, what are the values of x?

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Rewrite 4x^2-3x+9=2x+1 as 4x^2-5x+8 = 0


Here, a = 4, b = -5 and c = 8. Then,


5 plus or minus sqrt (25 -4(4)(8) )

x = ------------------------------------------------------

8

5 plus or minus sqrt (-103)

= --------------------------------------

8

5 plus or minus i*sqrt(103)

Then x = ----------------------------------------

8


= ---------------------------------------------

8

= ----------------------------

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3 years ago
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Answer:

All four options are correct.

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Option 1

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