Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Gggggggggggggggggggggggggggggggggggggg. It would be 7
Answer:
9feet
Step-by-step explanation:
Given the path of the toy modeled by the function f(x)=−x^2+4x+5, where x is the number of feet the toy is from Emmy and f(x) is the height of the toy.
AT maximum height, the velocity of the toy will be zero. Hence;
df(x)/dx = 0
-2x + 4 = 0
-2x = -4
x = -4/-2
x = 2
Get the maximum height;
Substitute x = 2 into the given function;
f(x)=−x^2+4x+5
f(2)=−2^2+4(2)+5
f(2) = -4+8+5
f(2) = 9feet
Hence the maximum height of the toy is 9feet
Given:
Principal = Rs. 6000
Rate of simple interest = 6% per annum.
Time = 4 years
To find:
The simple interest and amount.
Solution:
Formula for simple interest:

Where, P is principal, r is the rate of interest and t is the number of years.
Putting P=6000, r=6 and t=4, we get



Now,



Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.