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kakasveta [241]
4 years ago
9

Write 337,060 in expander form using exponentsd

Mathematics
1 answer:
Zinaida [17]4 years ago
4 0

Answer:

337060=(3 \times{10}^{5})+(3 \times {10}^{4})+(7 \times {10}^{3})+(6 \times10)

Step-by-step explanation:

Writing 337,060 in expanded form we obtain337060=300000+30000+7000+ 000+60+0

But because the value of the digit 0 in 337060 is 0, we can rewrite the expanded form as

337060= 300000+30000+7000+60

This can be written as

337060=(3 \times10000)+(3 \times 10000)+(7 \times1000)+(6 \times 10)

Using the exponent form we obtain

337060 = (3 \times {10}^{5})+(3 \times {10}^{4})+(7 \times {10}^{3}+(6 \times10)

Therefore the expanded

337060=(3\times{10}^{5})+(3 \times{10}^{4})+(7\times{10}^{3})+(6\times10)

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Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25
alexira [117]

Step-by-step explanation:

To check if a solution is extraneous, simply plug it back into the original equation.  If it works, then solution isn't extraneous.

√(2x−1) = 7

√(2(25)−1) = 7

√(50−1) = 7

√(49) = 7

7 = 7

So the solution isn't extraneous.

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3 years ago
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Vitek1552 [10]
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4 years ago
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Brainlist if right no lnks
zloy xaker [14]

Answer:∠1 and ∠5

Step-by-step explanation:

(A) ∠3 and ∠6  forms the interior angles on the same side of the transversal. Thus, this option is incorrect.

(B) ∠1 and ∠4 forms the linear pair on the straight line a, thus this option is incorrect.

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5 0
3 years ago
Los jornales de dos obreros suman S/.60. Si uno de ellos gana S/.12
8_murik_8 [283]

Answer:

Cada uno de ellos gana:

S/. 24

S/. 36

Step-by-step explanation:

Planteamiento:

a + b = 60

a = 12 + b

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

(12+b) + b = 60

2b + 12 = 60

2b = 60 - 12

2b = 48

b = 48/2

b = 24

de la segunda ecuación del planteamiento:

a = 12 + b

a = 12 + 24

a = 36

Check:

24 + 36 = 60

5 0
4 years ago
it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random samp
Lady_Fox [76]

Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Proportion of 0.6

This means that p = 0.6

Sample of 46

This means that n = 46

Mean and standard deviation:

\mu = p = 0.6

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722

Probability of obtaining a sample proportion less than 0.5.

p-value of Z when X = 0.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.5 - 0.6}{0.0722}

Z = -1.38

Z = -1.38 has a p-value of 0.0838

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

8 0
3 years ago
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