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Kisachek [45]
3 years ago
13

How do I solve this?...

Mathematics
1 answer:
kap26 [50]3 years ago
6 0
The cheap answer is, you can just multiply both sides by 6, that way you get rid of the denominator.

\bf 15-\cfrac{1}{6}n=\cfrac{1}{6}n-1\impliedby \times 6
\\\\\\
\boxed{6}\left( 15-\cfrac{1}{6}n \right)=\boxed{6}\left( \cfrac{1}{6}n-1 \right)
\\\\\\
\boxed{6}\cdot 15-\boxed{6}\cdot \cfrac{1}{6}n=\boxed{6}\cdot \cfrac{1}{6}n-\boxed{6}\cdot 1\implies 90-n=n-6
\\\\\\
90+6=n+n\implies 96=2n\implies \cfrac{96}{2}=n\implies 48=n

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Read 2 more answers
I need to find the area below! <br> HELP!
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