Assume the random variable X is normally distributed, with mean = 54 and standard deviation o = 8. Find the 15th percentile.
1 answer:
Answer:
45.712
Step-by-step explanation:
We need to find the Zscore of the area of 15 percent of the distribution ; using a Z table or calculator ;
Zscore of 15% of the distribution is : - 1.036
Using the Zscore formula :
Zscore = (x - mean) / standard deviation
Where, x = score
-1.036 = (x - 54) / 8
Cross multiply
-1.036 * 8 = x - 54
-1.288 = x - 54
x = - 8.288 + 54
x = 45.712
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