A. Y=-2 X-2y=6 B. Y=-2 X+2y=6 C. X=-2 2x-y=3 D. X=-2 2x+y=-3

Semmy [17]

It would be around 50

7 0

3 years ago

Earl worked 18 hours last week. If he had earned $2.00 an hour more but had worked only 15 hours, he would have earned the same

ruslelena [56]

Answer:

B) $10.00

Step-by-step explanation:

10 × 18 = 180

10 + 2 = 12

12 × 15 = 180

3 0

3 years ago

Read 2 more answers

How Many solutions are there for the following system. y = x² - 5x + 3 Y = x - 6

emmasim [6.3K]

Only one solution, x=3

7 0

3 years ago

Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12

e-lub [12.9K]

Answer:

The height of the pan is 2 inches.

Step-by-step explanation:

Given : Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12 inches and it's with is $10\frac{1}{2}$ inches.

To find : What is the height of the pan ?

Solution :

The volume of a rectangle or prism is

$V=l\times w\times h$

Where, l=12 inches is the length

$w=10\frac{1}{2}$ inches is the width

V=252 in.³ is the volume

h is the height

Substitute the value,

$252=12\times 10\frac{1}{2}\times h$

$252=12\times \frac{21}{2}\times h$

$h=\frac{252\times 2}{12\times 21}$

$h=2$

Therefore, the height of the pan is 2 inches.

7 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago