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valentinak56 [21]
4 years ago
10

A painter charges $15.92 per hour, plus an additional amount for the supplies. If he made $191.76 on a job where he worked 7 hou

rs, how much did the supplies cost?
Mathematics
1 answer:
NikAS [45]4 years ago
4 0

the answer to your question is $80.32

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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
NISA [10]

Answer:

Step-by-step explanation:

Here is the complete question.

Dominique, Marco, Roberto , and John work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company decides that the two individuals who get to attend will have their names drawn from a hat. This is like obtaining a simple random sample of size 2. (a) Determine the sample space of the experiment. That is, list all possible simple random samples of size n = 2. (b) What is the probability that Dominique and Marco attend the conference? (c) What is the probability that John attends the conference?  ​(d) What is the probability that John stays​ home?

Since there are four employees to select the two to send from. then for us to get the sample space for the experiment we need to merge all possible two employees and represent them as set.

Let D = Dominique, M = Marco, R = Roberto and J = John

a) The sample space for the experiment is the total number of possible outcomes that we can have. It is as given below

S = 4C2 = 4!/(4-2)!2! (Selecting 2 out of 4 employees)

Total sample space = 4!/2!2!

Total sample space = 4*3*2!/2!2

Total sample space = 12/2 = 6

The sample space are S = {DM, DR, DJ, MR, MJ, RJ}

b) Probability is the ratio of number of event to the sample space.

P = n(E)/n(S)

Given n(S) = 6

n(E) is the event of Dominique and Marco attending the conference.

E = {DM}

n(E) = 1

P(D and M) = 1/6

Hence  the probability that Dominique and Marco attend the conference is 1/6

c) For John to attend the conference, the event outcome will be given as;

E = {DJ, MJ, RJ}

n(E) = 3

n(S) = 6

Probability for John to attend the conference is 3/6 = 1/2

d) Probability that John stays at home = 1 - Prob (John attends the conference)

Probability that John stays at home = 1 - 1/2

Probability that John stays at home = 1/2

7 0
3 years ago
6th grade math I reallyyyyy neeedd helpp
UNO [17]
Hello!

Question 6:
To find the area of the pennant, we need to multiply the length by the width. 
12 x 18 = area
12 x 18 = 216
The answer is 216 square inches.

Question 7:
The perimeter of the square is 24cm and the area is 36 square cm.
The perimeter of the rectangle is 30cm and the area is 50 square cm. 
They have different perimeters and different areas.

I hope this helps you! Have a great day!
-Mal

4 0
3 years ago
Simplify the following expression 4/1/4-5/2
lorasvet [3.4K]

Answer:

1\frac{3}{4}

Step-by-step explanation:

4 \frac{1}{4} - \frac{5}{2} = 1 \frac{3}{4}

5 0
3 years ago
(-2,-1)(-1,2)(0,3)(1,4)(2,5) A: Function B: Not a function​
kupik [55]

Answer:

This answer is a function because there are no repeating x values. It is okay if there are repeating y values, the x values are the problem. This one has no repeats though so it is a function!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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