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sveta [45]
3 years ago
6

Please solve and show working for 13-((4/5)+(6/8))=

Mathematics
1 answer:
UNO [17]3 years ago
6 0
<span>13-((4/5)+(6/8))
Make your fractions have common denominators 
</span>13-((32/40)+(30/40))
Add your fractions and simplify
13-(62/40)
or
13-(31/20)
or
13-(1 11/20)
Then turn 13 into a fraction with a common denominator! Im going to use the second fraction method (31/20)
13 written as a fraction is 13/1, its LCD with 31/20 is 20. I now multiply the top and bottom by 20
260/20
Now I rewrite the problem again
(260/20)-(31/20)
Which equals
229/20!
This is your unsimplified answer
Finally you simplify and get
11 9/20

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A cave explorer is at an elevation of negative 38 feet. The explorer starts moving at a rate of negative 12 feet per minute. Ide
Ksivusya [100]

Answer:

-38 - 12x < 200

Step-by-step explanation:

Given,

The original elevation = -38 feet,

Also, the explorer starts moving at a rate of negative 12 feet per minute.

So, the distance covered by explorer after x minutes = -12x feet,

Thus, the final elevation = original elevation +  distance covered by explorer

= -38 - 12x

According to the question,

final elevation < -200 feet

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3 years ago
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Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept fo
Alla [95]

Answer:

\displaystyle y=-\frac{1}{2}x+4

Step-by-step explanation:

<u>Equation of a Line</u>

We can find the equation of a line by using two sets of data. It can be a pair of ordered pairs, or the slope and a point, or the slope and the y-intercept, or many other combinations of appropriate data.

We are given a line

y - 12 = 2x -8

And are required to find a line perpendicular to that line. Let's find the slope of the given line. Solving for y

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The coefficient of the x is the slope

m=2

The slope of the perpendicular line is the negative reciprocal of m, thus

\displaystyle m'=-\frac{1}{2}

We know the second line passes through (2,3). That is enough information to find the second equation:

y-y_o=m'(x-x_o)

\displaystyle y-3=-\frac{1}{2}(x-2)

Operating

\displaystyle y=-\frac{1}{2}(x-2)+3

Simplifying

\displaystyle y=-\frac{1}{2}x+4

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s344n2d4d5 [400]
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2 years ago
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Answer:

Step-by-step explanation:

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