The answer is B BECAUSE ALL YOU HAVE TO DO IS ADD ALL SIDES AND THEN MULTIPLY THEM
Answer:the answer is the first
Step-by-step explanation:
Because the expression can be written as -10r2/2r2+4+5r/2r2+4+3/2r2+4
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer:
Area=2232 square ft
Perimeter=206 ft
Step-by-step explanation:
given
the diagram is a rectangle
length=72 ft
width=31 ft
we know that
formula of the area of rectangle= length × width
Area=72×31 square ft
Area=2232 square ft
Now calculate the perimeter
perimeter of rectangle=2(length+width)
perimeter=2(72+31)
perimeter=2(103)
perimeter=206 ft
Answer:
<em>6</em>
Step-by-step explanation:
There are 2 options for 3 items.
So multiple 2 by 3, and you can have a range of 6 lunches able to be chosen.
2 x 3 = 6