2×5^{2} if you don't understand its 2 times 5 to the second power.
You cannot divide by zero, because that is undefined, it approaches infinity, which is not a real value. Some would say that division by zero is "not allowed" :P
So in this case the divisor cannot equal zero.
x^2+4x+3=0 There are many methods to factor, I'll complete the square, just for conciseness (and it is good to know how the quadratic formula is derived)
Divide by the leading coefficient, which is just 1 in this case...
Move the constant to the other side, subtract 3 from both sides
x^2+4x=-3 Halve the linear coefficient, square it, then add that value to both sides...(4/2)^2=2^2=4
x^2+4x+4=1 Now the left side is a perfect square...
(x+2)^2=1 Take the square root of both sides
x+2=±√1 subtract 2 from both sides
x=-2±√1
x=-2±1
x=-3 and -1
So if the equation equals zero when x=-3 and -1, it's factors are:
(x+3)(x+1)
So x cannot equal -3 or -1, otherwise your original equation would have division by zero.
Answer:
B.
Step-by-step explanation:
Sam median = 12 which has 3 points scored.
Daniel median = 16 which has 3 points scored.
Both scored the same amount of data which is 3 points.
Both the ranges are 16. so it cant be A or C.
1.20(35)
this would be the same as :
(1 + 0.2)* 35 <==
or it also could have been 35 + 0.20(35)
Answer:
3a + 2b
is cube root of 27a^3+54a^2b+36ab^2+8b^3