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3 years ago

What is the selling price of a set of scrubs if the markup is 80% of the cost, and the cost is $37.99?

Mathematics

1 answer:

attashe74 [19]3 years ago

7 0

Answer:

Discount = Original Price x Discount %/100

Discount = 37.99 × 80/100

Discount = 37.99 x 0.8

You save = $30.39

Final Price = Original Price - Discount

Final Price = 37.99 - 30.392

Final Price = $7.60

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Whats 9,032,504.75 in expanded form

Verizon [17]

*sigh* 9,000,000.00 +30,000.00 +2,000.00+ 500.00 + 4.00 + 0.70 + 0.05.

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3 years ago

Solve the initial value problem yy′+x=x2+y2‾‾‾‾‾‾‾√ with y(1)=8‾√. To solve this, we should use the substitution u= x^2+y^2 help

leva [86]

Looks like the equation is

$yy'+x=\sqrt{x^2+y^2}$

Substitute $u(x)=x^2+y(x)^2$ , so that $u'=2x+2yy'$ . Then the equation is the same as

$\dfrac{u'-2x}2+x=\sqrt u\implies u'=2\sqrt u\implies\dfrac{\mathrm du}{2\sqrt u}=\mathrm dx$

Integrate both sides to get

$\sqrt u=C\implies\sqrt{x^2+y^2}=C$

Given that $y(1)=\sqrt8$ , we have

$\sqrt{1^2+(\sqrt8)^2}=C\implies C=3$

so the solution is

$\sqrt{x^2+y^2}=3$

7 0

2 years ago

Emerson earns money from walking dogs and answering surveys. He earns $5 a week for each dog he walks and $0.10 for each survey

maria [59]

Part A: X=(35-(100*0.10))/5 35= 5X+(100*0.10)
Where X is the number of dogs he walked.

Part B: To solve the equation just simplify it by using inverse operations. It should give you 5 dogs walked. The algebraic property justifying this is inverse operations.

Part C: Emerson walked 5 dogs last week.

8 0

2 years ago

Read 2 more answers

Write the equation if the line that passes through (4,5) and has a slope of m=3

andrew11 [14]

Answer:

y = 3x - 7

Step-by-step explanation:

The <em>point-slope formula</em> for a straight line is

y – y₁ = m(x – x₁)

x₁ = 4; y₁ = 5; m = 3 Substitute the values

y – 5 = 3(x - 4) Remove parentheses

y – 5 = 3x - 12 Add 5 to each side

y = 3x - 7

The graph is a straight line with a y-intercept at y = -7 and a slope = 12/4 = 3.

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2 years ago

Identify the parts of the expression. Then write a word expression for the numerical or algebraic expression.

mixas84 [53]

2 = coefficient
e = variable
- = operation
f = variable

2e = 2 × e

f subtracted from the product of two and e

3 0

3 years ago