Answer:
just take speed =distance ÷time
dustance is speedxtime
14x1.61=22.54÷60 to change to min =0.37km per minute
0.40x0.37= 0.148 km
perhaps I may get wrong
Answer:
DCB ~ RST
JKL ~ JTU
Step-by-step explanation:
The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Given an equation showing profits of A Christmas vendor as
P=-0.1
+30g-1200.
We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.
To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.
665.60=-0.1
+30g-1200
0.1
-30g+1200+665.60=0
0.1
-30g+1865.60=0
Divide the above equation by 0.1.
-300g+18656=0
Solving for g we get,
g=[300±
]/2*1
g=[300±![\sqrt{90000-74624}]/2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-74624%7D%5D%2F2)
g=[300±
]/2
g=(300±124)/2
g=(300+124)/2 , g=(300-124)/2
g=424/2, g=176/2
g=212,88
Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.
Put the value of P=1500 in equation P=-0.1
+30g-1200.
-0.1
+30g-1200=1500
0.1
-30g+1500+1200=0
0.1
-30g+2700=0
Dividing equation by 0.1.
-300g+27000=0
Solving the equation for finding value of g.
g=[300±
]/2*1
=[300±![\sqrt{90000-108000}] /2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-108000%7D%5D%20%2F2)
=[300±
]/2
Because
comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.
Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Learn more about equation at brainly.com/question/2972832
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Average speed = (distance covered) / (time to cover the distance)
= (500 miles) / (6.7 hours)
= (500 / 6.7) (mile/hour)
= 74.63 miles per hour.
I imagine there were quite a number of pit stops included in that.
This is faster than I expected when I first read your question.
That's really gettin' with it for cars in 1911 !
∠SCD =150 and ∠BCD=174 (Given)
∠BCS + ∠SCD = ∠BCD (Segment Addition Postulate)
∠BCS + 150 = 174 (Substitution)
∠BCS = 24 (Subtraction Property of Equality)
Answer: 24