Use the empirical rule to find a reasonable estimate for P(z ≤ 0.82).

Mathematics

2 answers:

prisoha [69]4 years ago

8 0

The next answer is 79%

edge2020

kifflom [539]4 years ago

7 0

The answer is 80%..................

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What is the surface area? 10 cm 7 cm 3 cm square centimeters

alexandr1967 [171]

Answer:

242cm^2

Step-by-step explanation:

The formula for surface area of a rectangular(assuming that's what you have) is Perimeter of the Base(height) + 2(Area of the Base)

Or you could add up all the sides, or use this formula

SA=2(length*width)+2(length*height)+2(height*width)

2×(10×7 + 10×3 + 7×3)

helpful links:

https://www.khanacademy.org/math/ basic-geo/basic-geo-volume-sa/basic-geometry-surface-area/v/surface-area-of-a-box

http://www.math.com/tables/geometry/surfareas.htm

https://www.basic-mathematics.com/surface-area-formula.html

6 0

3 years ago

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$