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3 years ago

TV is 17 inches in length and width of 8 inches how tall is a TV

Mathematics

2 answers:

Vanyuwa [196]3 years ago

5 0

Answer:

136 inches

Step-by-step explanation:

l x w = area

so 17 x 8 = 136

alexandr1967 [171]3 years ago

3 0

Answer: the height of the tv is 15 inches

Step-by-step explanation: use pathagoreans theorem

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2. Five pigs were weighed daily to regulate caloric

kotykmax [81]

Answer: -1.409, -1.48, 0.007 , 0.10, 0.17

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4 0

3 years ago

Will give brainliest answer What is the value of a21? A.36 B. 58 C.60 D. 41

Strike441 [17]

Answer:

Step-by-step explanation:

Matrix Multiplication follows a row-column format. In order to compute this, you must be familiar with vector dot products.

With that in mind, lets get straight into it.

The order that matrix multiplication follows means that the terms in the result are filled in left to right, then top to bottom.

Therefore, a21 will be the 3 value that is computed. This is important becuase this allows to directly compute a21, instead of using up a lot of time computing all the values before.

As a21 is located in the bottom row 1st column, we take the dot product of the 2nd row in matrix 1 and the 1 column in matrix two.

So we have:

(7 2) dot (5 3) = 7*5 + 2*3 = 41

7 0

3 years ago

The vertex of ∠ABC is <br> A<br> B <br> C

PSYCHO15rus [73]

Answer:

The vertex is b

Step-by-step explanation:

3 0

4 years ago

(0, -8), (5, 3), (-4, 3), (9, 2) Domain range and function

aliina [53]

Answer:

domain: (0, 5, -4, 9)

range: (-8, 3, 2)

Step-by-step explanation:

6 0

3 years ago

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°

7 0

4 years ago

Read 2 more answers