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barxatty [35]
2 years ago
11

Which expression can be used to find the value of expression below -(7/10) + 2/8 + 1/10 - (4/8)

Mathematics
1 answer:
maks197457 [2]2 years ago
4 0

Answer:

(-17)/20

Step-by-step explanation:

Simplify the following:

-7/10 + 2/8 + 1/10 - 4/8

The gcd of 2 and 8 is 2, so 2/8 = (2×1)/(2×4) = 2/2×1/4 = 1/4:

-7/10 + 1/4 + 1/10 - 4/8

The gcd of -4 and 8 is 4, so (-4)/8 = (4 (-1))/(4×2) = 4/4×(-1)/2 = (-1)/2:

-7/10 + 1/4 + 1/10 + -1/2

Put -7/10 + 1/4 + 1/10 - 1/2 over the common denominator 20. -7/10 + 1/4 + 1/10 - 1/2 = (2 (-7))/20 + 5/20 + 2/20 - 10/20:

(2 (-7))/20 + 5/20 + 2/20 - 10/20

2 (-7) = -14:

(-14)/20 + 5/20 + 2/20 - 10/20

-14/20 + 5/20 + 2/20 - 10/20 = (-14 + 5 + 2 - 10)/20:

(-14 + 5 + 2 - 10)/20

-14 + 5 + 2 - 10 = (5 + 2) - (14 + 10):

((5 + 2) - (14 + 10))/20

5 + 2 = 7:

(7 - (14 + 10))/20

| 1 | 4

+ | 1 | 0

| 2 | 4:

(7 - 24)/20

7 - 24 = -(24 - 7):

(-(24 - 7))/20

| 1 | 14

| 2 | 4

- | | 7

| 1 | 7:

Answer: (-17)/20

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qwelly [4]

Answer: \frac{11tc+5g}{66t}=n

Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

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2 years ago
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Rus_ich [418]
Option A is the answer
6 0
3 years ago
two brothers marco and fernando are training for a marathon marco runs at a rate of 6miles per hor. Fernando funs at at a rate o
satela [25.4K]
We know that
speed=distance/time
solve for time
time=distance/speed

in this problem
<span>Marco runs at a rate of 6 miles per hour. 
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
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time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)

Alternative Method
Let 
x---------> Fernando's distance when Marco is 0.3 miles apart

</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
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</span>Marco runs at a rate of 6 miles per hour. 
for distance=x-0.30
time=(x-0.30)/6------> equation 2

equate equation 1 and equation 2
 7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles

time=x/7.2-----1.8/7.2=0.25 hour
6 0
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8 0
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-12 h = -42

h = 3.5 pounds

sorry if this was late

8 0
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