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V125BC [204]
3 years ago
8

, list the first five terms of each sequence, and identify them as arithmetic or geometric.

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Each element is 2/3 times the previous one, so that's a geometric sequence.

6×(2/3)=4, 4×(2/3)=8/3, 8/3×(2/3)=16/9, 16/9×(2/3)=32/27

Answer: 6, 4, 8/3, 16/9, 32/27

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The temperature was -6°F at Rosewood that the temperature was 0°F what represents the change in temperature
vlabodo [156]

Answer:

+ 6°F

Step-by-step explanation:

Change is (Final - Initial)  [Change is subtract old value from new value]

(0°F -(-6°F)) = +6°F

8 0
3 years ago
Harry, Peter and 7 girls sit in a row. Harry can't sit in an end seat. In how many ways can they be arranged?
Sonja [21]
All possibilities = 9! 
possibilities that harry sits at an end = 8! + 8! 
possibilities that harry doesn't sit at an end = 9! - 8! -8! 

4 0
3 years ago
Read 2 more answers
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
Can someone explain this for me ? :)
ruslelena [56]
34! Find the area of each of the six sides and then add them up:)
7 0
3 years ago
Esther pays $355 per month for 5 years for a car. She made a down payment of $2,500. If the loan costs 7.1% per year compounded
oksano4ka [1.4K]
The cash price of the car includes the amount of the loan plus the amount of the down payment
Cash price=the loan of the car+down payment

First find the amount of the loan by using the formula of the present value of an annuity ordinary which is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv the amount of the loan ?
PMT payment per month 355
R interest rate 0.071
K compounded monthly 12
N time 5years
Pv=355×((1−(1+0.071÷12)^(−12
×5))÷(0.071÷12))
=17,885.56

Cash price=17,885.56+2,500
=20,385.56....answer
5 0
4 years ago
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