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Orlov [11]
4 years ago
13

6.14 x 10 to the power of negative 9 in standard form

Mathematics
2 answers:
Dafna1 [17]4 years ago
6 0
6.14 x 10^-9 = 0.00000000614
aliya0001 [1]4 years ago
3 0
0.00000000614 is the standard form
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I NEED THIS ANSWERED ASAPPPPPP!!!!!!!!!!!!!1111 THANKS
Katyanochek1 [597]
The division is using extra zeros.
2 * 16  = 32, but 3200 was placed below 3426.

Now 1 * 16 = 16, so 160 goes below 226.
The number that goes in the box is 160.
8 0
3 years ago
How many solutions does y=5x+12 and y=5x+18
Mrrafil [7]

Answer:

there is no solution for these linear equations in two variables.

since a1 (y) = a2 (y)

         b1 (5x) = b2 (5x)

  but, c1 (12) not equal to c2 (18)

8 0
3 years ago
Read 2 more answers
You roll a number cube twice first roll is a four second roll I roll a even number is that a defendant or independent situation
Katyanochek1 [597]
Independent because the ratio of the second cube is the same (1:6), and it isn't affected by the result of the first cube
7 0
3 years ago
Mr. Bradley purchased 20 trays of flowers. Each tray had 3 dozen flowers. Mr. Bradley's total for all the flowers was 273.60. Al
aev [14]

Answer: Each flower costs $0.38.

Step-by-step explanation:

1 dozen = 12 units

Flowers in each tray = 3 dozen = 3 x 12 = 36

Flowers in 20 trays = 20 x 36 = 720

Price of 20 trays = $ 273.60

Price of each flower = (Price of 20 trays  ) ÷ (Flowers in 20 trays)

= 273.60 ÷ 720

= $ 0.38

Hence, each flower costs $0.38.

7 0
3 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
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