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Anton [14]
4 years ago
5

Determine the value of the variable -4y + 2y + 2 < -8 + 2

Mathematics
1 answer:
AfilCa [17]4 years ago
3 0

Answer:

SOrry i cant heklp u

Step-by-step explanation:

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What is 3 1/4 - 4 1/2<br>????
nlexa [21]

you have to make sure that they have the same denominator so

31/4 -4 2/4

= - 1 1/4

hope this helped you hon


7 0
4 years ago
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Need this done in five omgg pls help 19 points
Lyrx [107]

6.64mm² multiply the cm and get that

8 0
3 years ago
Pls help me**will give brainlest answer**
dusya [7]

Answer:

S = 4

Step-by-step explanation:

5 0
3 years ago
A train travels 600 km in 4 hours. What is the speed of the train? 0. 007 km/h 604 km/h 150 km/h 2,400 km/h.
vekshin1

Based on the distance travelled and the time taken, the speed of the train was <u>150 km/h</u>

Speed can be calculated by the formula:

<em>= Distance / Time </em>

Distance = 600 km

Time = 4 hours

Solving will give:

= 600 / 4

= 150 km/ h

In conclusion, the train was going at 150 km/h

<em>Find out more on speed at brainly.com/question/3004254</em>

4 0
3 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
7 0
3 years ago
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