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Rudiy27
3 years ago
15

Use these properties to rewrite 7/4 + 1/2 + 5/3 + 1/3 + 1/4 + 1/2 in a way that makes the addition easier. Explain how your chan

ges simplify the addition

Mathematics
2 answers:
zzz [600]3 years ago
4 0

Answer:

1 + 3 5/12 + 7/12

Step-by-step explanation:

The changes simplify the addition by  making the equation shorter and easier to understand and solve. (I am sure you could add the 3 5/12 + 7/12 to make it even shorter but I decided not to) Hope this helps!

Reptile [31]3 years ago
3 0
It makes the addition easier if you combine like terms like the two 1/2s and then make them all have the denominator of 12 (changing the numerators to equal it out)
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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Use the power series representation of f(x)=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1-5x%7D%20" id="TexFormula1" t
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\dfrac1{1-5x}=\displaystyle\sum_{n\ge0}(5x)^n

and so

g(x)=\dfrac{15}{1-5x}=15\displaystyle\sum_{n\ge0}(5x)^n=3\sum_{n\ge0}5^{n+1}x^n

which is, again, only valid for |5x|.
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Alaska, Hawaii and Washington have active volcanoes. Alaska has 43, Hawaii has 5 and Washington has v. If they have 52 active vo
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Answer:

five

Step-by-step explanation:

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2 years ago
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3 0
3 years ago
YOU Will be SHOWERED With POINTS IF U HELP ME
Volgvan

Answer: C

<u>Step-by-step explanation:</u>

f(x) = 26.2 - 0.1x

f(100) = 26.2 - 0.1(100)

         = 26.2 = 10.0

         = 16.2

f(5-) = 26.2 - 0.1(50)

       = 26.2 - 5.0

       = 21.2

******************************************************

Answer: D

<u>Step-by-step explanation:</u>

f(x) = 2|x - 3| + 1

2 units right: f(x) = 2|x - (3 + 2)| + 1

                           = 2|x - 5| + 1

3 0
3 years ago
Read 2 more answers
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