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Rudiy27
3 years ago
15

Use these properties to rewrite 7/4 + 1/2 + 5/3 + 1/3 + 1/4 + 1/2 in a way that makes the addition easier. Explain how your chan

ges simplify the addition

Mathematics
2 answers:
zzz [600]3 years ago
4 0

Answer:

1 + 3 5/12 + 7/12

Step-by-step explanation:

The changes simplify the addition by  making the equation shorter and easier to understand and solve. (I am sure you could add the 3 5/12 + 7/12 to make it even shorter but I decided not to) Hope this helps!

Reptile [31]3 years ago
3 0
It makes the addition easier if you combine like terms like the two 1/2s and then make them all have the denominator of 12 (changing the numerators to equal it out)
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Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
oksano4ka [1.4K]

Answer:

1/q^30 (startfraction 1 over q subscript 30 baseline end fraction)

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B
riadik2000 [5.3K]

Let

S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n

where we assume |r| < 1. Multiplying on both sides by r gives

r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}

and subtracting this from S_n gives

(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}

As n → ∞, the exponential term will converge to 0, and the partial sums S_n will converge to

\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}

Now, we're given

a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a

a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}

We must have |r| < 1 since both sums converge, so

\dfrac{15}a = \dfrac1{1-r}

\dfrac{150}{a^2} = \dfrac1{1-r^2}

Solving for r by substitution, we have

\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)

\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}

Recalling the difference of squares identity, we have

\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}

We've already confirmed r ≠ 1, so we can simplify this to

\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15

It follows that

\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12

and so the sum we want is

ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0
2 years ago
Do you add or multiple?
BaLLatris [955]
Add your welcome I think
3 0
2 years ago
1. Josefina ha pintado 2/4 de una pared y su hermano<br>  ¿Cuánto han pintado entre los dos?
Irina18 [472]

Answer  67+67=6886

Step-by-step explanation:

8 0
3 years ago
What survival rate in the 10th year would make the average of loss over the 10 year period equal to 38.0%
Marat540 [252]

Answer: 63%

Step-by-step explanation:

<u>First step</u>

Find the 10th year rate of loss that will make the average of loss over the 10 years to equal 38.0%.

Assume this rate is x;

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x = 37%

<u>Second step - Survival rate</u>

The survival rate is calculated by;

= 1 - rate of loss

= 1 - 37%

= 63%

7 0
2 years ago
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