The diameter and radius of a circle with circumference of 36 meters are 11.46 meters and 5.73 meters respectively.
<h3>How to find diameter and radius of a circle using circumference?</h3>
circumference of a circle is the perimeter of a circle. Therefore,
circumference of a circle = 2πr
where
Therefore,
36 = 2 × π × r
36 / 2 = πr
18 = πr
r = 18 / 3.14
r = 5.73248407643
radius = 5.73 meters
radius = diameter / 2
Therefore,
diameter = 2 × 5.73 = 11.46 meters
learn more on circle here: brainly.com/question/12014373
Filling the total revenue, average revenue, and marginal revenue table for Dani is as follows:
Quantity Total revenue ($) Average revenue Marginal revenue
of roses
1 $8.00 $8.00 $8.00
2 $16.00 $8.00 $8.00
3 $24.00 $8.00 $8.00
4 $32.00 $8.00 $8.00
5 $40.00 $8.00 $8.00
<h3>How to calculate the different revenues?</h3>
- Total revenue = Quantity x Sales Price
- Average revenue = Total revenue/Quantity
- Marginal revenue = Difference between Initial Revenue and Current Revenue
<h3>Data and Calculations:</h3>
Quantity Total revenue ($) Average revenue Marginal revenue
of roses
1
2
3
4
5
Price per rose = $8
Thus, when Dani sells 5 units of roses, he will get a total revenue of $40, though the marginal and average revenues remain at $8, respectively.
Learn more about marginal and average revenues at brainly.com/question/25623677
The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;
⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
Answer:
2
Explanation:
it says all frekas are jekas AND before that it stated that every heka is either teta or jeka
so that means some jekas are heka making some frekas hekas