How do I graph the following ordered pairs (0, -4), (3,1) (6, 6)? this is for 5x-3y=12.
1 answer:
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Answer:
he equation of the line is parallel to the given line and passing through the point C( 1,4) is x - 8 y + 31=0
slope intercept form
Step-by-step explanation:
<u><em>Explanation:</em></u>-
Given equation of the line
y = 1/8x-4
8 y = x - 32
x - 8 y -32=0
<em>The equation of the line is parallel to the given line a x + b y + k=0</em>
<em> x - 8 y + k=0</em>
<em>This line is passing through the point ( 1,4)</em>
<em> x - 8 y + k=0</em>
1 - 32 + k =0
k = 31
The equation of the line is parallel to the given line and passing through the point C( 1,4) is x - 8 y + 31=0
<em>slope intercept form</em>
<em> 8 y = x + 31</em>