Question

Write an equation for the line parallel to the given line that contains C. C(1,4); y = 1/8x-4 (Write in slope intercept form)

Answer 1

Answer:

he equation of the line is parallel to the given line and passing through the point C( 1,4) is        x - 8 y + 31=0

slope intercept form

                     $y = \frac{x}{8} + \frac{31}{8}$

Step-by-step explanation:

Explanation:-

Given equation of the line  

                                y = 1/8x-4

                               8 y = x - 32

                         x - 8 y -32=0

The equation of the line is parallel to the given line a x + b y + k=0

                                                                                   x - 8 y + k=0

This line is passing through the point ( 1,4)

             x - 8 y + k=0

             1 - 32 + k =0

                  k = 31

The equation of the line is parallel to the given line and passing through the point C( 1,4) is        x - 8 y + 31=0

slope intercept form

                         8 y = x + 31

                          $y = \frac{x}{8} + \frac{31}{8}$