I can't see the price for shoe rentals but the expression should be
total cost in dollars (y)=(number of games (3) X the price of a game ($4)) + price of shoes. Plug in your values and you should get y=$12+shoes.
Answer:
90+30=120
180-120=60 this is degree measure
![\bf sin(x)[csc(x)-sin(x)]~~=~~cos^2(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)\left[\cfrac{1}{sin(x)}-\cfrac{sin(x)}{1} \right]\implies \underline{sin(x)}\left[\cfrac{1-sin^2(x)}{\underline{sin(x)}} \right] \\\\\\ 1-sin^2(x)\implies cos^2(x)](https://tex.z-dn.net/?f=%5Cbf%20sin%28x%29%5Bcsc%28x%29-sin%28x%29%5D~~%3D~~cos%5E2%28x%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20sin%28x%29%5Cleft%5B%5Ccfrac%7B1%7D%7Bsin%28x%29%7D-%5Ccfrac%7Bsin%28x%29%7D%7B1%7D%20%5Cright%5D%5Cimplies%20%5Cunderline%7Bsin%28x%29%7D%5Cleft%5B%5Ccfrac%7B1-sin%5E2%28x%29%7D%7B%5Cunderline%7Bsin%28x%29%7D%7D%20%5Cright%5D%20%5C%5C%5C%5C%5C%5C%201-sin%5E2%28x%29%5Cimplies%20cos%5E2%28x%29)
recall again, sin²(θ) + cos²(θ) = 1.
Area of each side triangle is 1/2*8*15 = 60. There are 5 of them so the triangles have surface area 300. the pentagon's area 1/2*apothegm*sidelength*sides = 1/2*5.5*8*5 = 110. The total area is therefore 300+110 = 410
Answer:
<4 = 126
<7 = 55
Step-by-step explanation:
Remark
There are only 2 answers to this question. <4 has one of them and <7 has the other one. <7 is acute. <2 is obtuse.
Givens
<2 = 55 degrees
Solution
<4 is the supplement of <2
Therefore <4 + <2 = 180 A straight line has an angle of 180°
<4 + 55 = 180
<4 = 180 - 55
<4 = 125
So <7 is either 55 or 125. Since <7 is acute, it is 55 degrees but we have another way of proving it.
<4 + <6 = 180 degrees Interior angles on the same side of the transversal are supplementary
125 + <6 = 180
<6 = 180 - 125
<6 = 55
<7 =<6 Vertically opposite angles are equal.
<7 = 55 degrees.
