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VLD [36.1K]
4 years ago
14

Our 7th grade math class was studying an experiment. Each group of students were given 2 paper bags. In one bag labeled A, there

will be 5 different brands of chips. In the second bag labeled B, there will be the same 5 brands of chips. If a bag of chips is drawn from each bag, what is the probability of NOT drawing your favorite brand?
Mathematics
1 answer:
Dimas [21]4 years ago
6 0
Wouldn't the probability depend on the brand? So the answer would be 100%
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3/9+2/9=?/9<br> Help a brother out
Ahat [919]

Answer:

5/9

Step-by-step explanation:

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4 years ago
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30 POINTS! Consider the system of linear equations and the matrix equations below.
fiasKO [112]

Answer:

Option C is correct.

Step-by-step explanation:

-x+3y=2

4x-2y=22

In matrix form is represented as:

\left[\begin{array}{cc}-1&3\\4&-2\end{array}\right] \left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{c}2&22\end{array}\right]

AX=B

X = A^{-1}B

A^{-1} = |A|/Adj A

|A| = (-1)(-2)-(3)(4)

|A| = 2-12

|A| = -10

Adj A = \left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]

A^-1 = -1/10\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]

A^-1 = 1/10\left[\begin{array}{cc}2&3\\4&1\end{array}\right]

X= A^-1 B

X = 1/10\left[\begin{array}{cc}2&3\\4&1\end{array}\right]\left[\begin{array}{c}2&22\end{array}\right]

X=1/10X=1/10\left[\begin{array}{c}2*2+3*22\\4*2+1*22\end{array}\right]\\X=1/10\left[\begin{array}{c}4+66\\8+22\end{array}\right]\\X=1/10\left[\begin{array}{c}70\\30\end{array}\right]\\X=\left[\begin{array}{c}70/10\\30/10\end{array}\right]\\X=\left[\begin{array}{c}7\\3\end{array}\right]

So, x = 7 and y =3

Hence Option C is correct.

4 0
3 years ago
Read 2 more answers
Find the probability that the senator was in the Democratic party, given that the senator was returning to office.
shutvik [7]

Answer:

The probability that the senator was in the Democratic party, given that the senator was returning to office is 0.4715.

Step-by-step explanation:

The complete question is:

Sophia made the following two-way table categorizing the US senators in 2015 by their political party and whether or not it was their first term in the senate.

                   Democratic         Republican         Independent        Total

First Term           11                          28                        11                     50

Returning           33                         26                        11                     70

Total                   44                         54                        22                  120

Find the probability that the senator was in the Democratic party, given that the senator was returning to office.

Solution:

The conditional probability of an event <em>A</em> given that another event <em>X</em> has already occurred is given by:

P(A|X)=\frac{P(A\cap X)}{P(X)}

The probability of an event <em>E</em> is given by the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability of selecting an US senator who is a Democratic and was returning to office as follows:

P(D\cap R)=\frac{33}{120}=0.275

Compute the probability of selecting an US senator who was returning to office as follows:

P(R)=\frac{70}{120}=0.5833

Compute the conditional probability, P (D | R) as follows:

P(D|R)=\frac{P(D\cap R)}{P(R)}

            =\frac{0.275}{0.5833}\\\\=0.4714555\\\\\approx 0.4715

Thus, the probability that the senator was in the Democratic party, given that the senator was returning to office is 0.4715.

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When you multiply 3 1/4 by a number greater than one, you will get the answer greater than 3 1/4. 
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