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olasank [31]
4 years ago
5

How are linear functions used in everyday life?

Mathematics
2 answers:
GREYUIT [131]4 years ago
8 0

Answer:

Step-by-step explanation:

Almost any situation where there is an unknown quantity can be represented by a linear equation, like figuring out income over time, calculating mileage rates, or predicting profit. Many people use linear equations every day, even if they do the calculations in their head without drawing a line graph.

Romashka [77]4 years ago
5 0

Answer:

They don't bro

Step-by-step explanation:They should teach us how to do stuff that will actually help us in real world situations

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41 coins, consisting of nickels and quarters, have a total value of $4.65. How many coins of each kind are there?
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Which of the following is not a kind of consumer credit?
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3 years ago
find the equation of the line passing through the given point and perpendicular to the given equation write your answer in slope
Paraphin [41]

Slope-intercept form:

y = mx + b      "m" is the slope, "b" is the y-intercept


For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2



3.) y = 2x - 2

The given line's slope is 2, so the perpendicular line's slope is -1/2

y=-\frac{1}{2}x+b To find "b", plug in the point (-5 , 5) into the equation

5=-\frac{1}{2}(-5)+b

5=\frac{5}{2}+b     Subtract 5/2 on both sides

5-\frac{5}{2}=b   Make the denominators the same

\frac{10}{2}-\frac{5}{2}=b

\frac{5}{2}=b


y=-\frac{1}{2}x+\frac{5}{2}



4.) -6x + 5y = -10     Get "y" by itself, add 6x on both sides

5y = -10 + 6x          Divide 5 on both sides

y=-2+\frac{6}{5}x

The given line's slope is 6/5, so the perpendicular line's slope is -5/6.

y=-\frac{5}{6}x+b       Plug in (-2, 5)

5 = -\frac{5}{6}(-2)+b

5=\frac{10}{6}+b\\ 5=\frac{5}{3}+b    Subtract 5/3 on both sides

5-\frac{5}{3} =b    Make the denominators the same

\frac{15}{3}-\frac{5}{3}=b\\\frac{10}{3} =b


y = -\frac{5}{6}x+\frac{10}{3}



7.) Perpendicular line's slope is -2

y = -2x + b      Plug in (1,4)

4 = -2(1) + b

4 = -2 + b

6 = b


y = -2x + 6



8.) Perpendicular line's slope is -1/4

y = -\frac{1}{4}x+b     Plug in (-5 , 2)

2=-\frac{1}{4}(-5)+b

2 = \frac{5}{4}+b    Subtract 5/4 on both sides

2-\frac{5}{4}=b     Make the denominators the same

\frac{8}{4}-\frac{5}{4}=b

\frac{3}{4}=b


y=-\frac{1}{4}x+\frac{3}{4}

5 0
3 years ago
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