Car B and E are speeding up, while car C is slowing down.
Step-by-step explanation:
Acceleration (a) is the rate of change of velocity with time.It is calculated by dividing the change in velocity (Δv) with the time taken for the change to occur.In this question , the time is 10 sec in all cases.You divide the velocity in km/h by 3.6 to convert to m/s
In Car A
Δv=8.33-8.33=0m/s
t=10s
a=0 m/s² ⇒car is moving with same speed and in the same direction
Car B
Δv=5.55-0=5.55
t=10
a=5.55/10 =0.555 m/s² ⇒car is speeding up
Car C
Δv = 0-8.33= -8.33 m/s
t= 10
a= -8.33/10 = -0.833 m/s² ⇒car is slowing down
Car D
Δv= 0-0 =0
t=10s
a=0/10 =0 m/s² ⇒car is at rest
Car E
Δv = 8.33-5.55=2.78
t=10
a=2.78/10 = 0.278 m/s²⇒car is speeding up
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To find acceleration : brainly.com/question/13154163
Keyword : velocity
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x+142 =3x+64
subtract x from each side
142 = 2x+64
subtract 64 from each side
142-64 = 2x
78=2x
divide by 2
78/2 = x
x=39
The number is 39
Let's do these in steps. Remember to show your work
#1. Convert into a improper fraction.
3 x 2 x 1 over 2cm.
#2. Simplify 3 x 2 to 6.
6 + 1 over 2cm.
#3. Change 6+1 to 7.
7 over 2m.
We finally get 7 over 2, but that rounded would be 7. So B would be our answer.
We have been given that Sebastian got estimates from 7 companies for his kitchen remodel: $ 27,500 ; $31,000 ; $36,000 ; $92,000; $29,000 ; $30,500 ; $28,500. We are asked to find the best measure of center for the given data.
We can see that our given data set has a large valued data point that is $92,000.
We know that mean is very much affected by large valued outliers. The data point $92,000 will increase the mean. Therefore, mean is not a best measure of center for given data.
We know that median is very less affected by outliers, therefore, median will be best measure of center for the given data.
1/4 the second one i think it could be that