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Delvig [45]
2 years ago
11

Please show work! 99 points plus brainliest!

Mathematics
2 answers:
maxonik [38]2 years ago
6 0
A) 6a=5b so a=5/6*b a/b=5/6
b) 6a=5b so 6/5*a=b b/a=6/5
c) a/b=5/6 so (a/b)*(2/7)=2a/7b=(2/7)(5/6)=(5/21)
d) 6a=5b so b=6a/5 Thus (a+b)/b=(a+6a/5)/(6a/5)=(11a/5)/(6a/5)=11/6
e) 6a=5b so a=5b/6 Thus (a+b)/(5a)=(5b/6+b)/(5*5b/6)=(11b/6)/(25b/6)=11/25
f) (3a+3b)/(a+b)=3=3/1

Note, I wasn't quite sure what you meant by \frac
EastWind [94]2 years ago
6 0
I know E and F

e) 6a=5b so a=5b/6 Thus (a+b)/(5a)=(5b/6+b)/(5*5b/6)=(11b/6)/(25/6)=11/25
f) (3a+3b)/(a+b)=3=3/1
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What is the sum of the first 50 terms of the series 2 + 17 + 32 + 47+ ...?​
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\huge\boxed{18,475}

Step-by-step explanation:

The terms of this sum make the arithmetic sequence.

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