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Sergio039 [100]
4 years ago
7

Conditional Probability

Mathematics
2 answers:
PilotLPTM [1.2K]4 years ago
7 0

Answer:

Step-by-step explanation:

Total number of persons = 37

Number of girl and sophomore= 9

Prob(girl/sophomore) = 9/37

Alja [10]4 years ago
3 0

Yo sup??

P(A|B)=P(A∩B)/P(B)

P(A∩B)=probability of finding a girl and is sophomore

P(B)=probability of finding a sophomore

P(A|B)=9/10

Hope this helps.

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The drama club is selling tickets to their play to raise money for the show's expenses. They are selling both adult tickets and
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

0 ≤ aa+ss ≤ 100

5 0
3 years ago
Let p and q be rational. Prove that p+q is rational
Contact [7]

Let p and q rational numbers (what does it means?), then, p and q coul be written as

p = \frac{a}{b},a, b \in \mathbb{Z}, b \neq 0\\\\q = \frac{c}{d}, c,d \in \mathbb{Z}, d \neq 0

then,

p +q = \frac{a}{b} + \frac{c}{d} = \frac{ad +bc}{bd}

and we know that ad+bc is an integer, so, p +q is a rational number.

4 0
3 years ago
What is the radius of a circle with an area of 28.26 square feet
Svetlanka [38]

Answer:

The radius is 3 square feet.

(Working is shown in the picture)

6 0
3 years ago
Professor Liu gave the same quiz to the students in her morning class and in her afternoon class. The average (arithmetic mean)
natka813 [3]

Answer:

Afternoon class has more students.

Step-by-step explanation:

Let m be the number of students in the morning class and n be the number of students in the afternoon class.

The average score for the students in the morning class was 80, then the sum of their scores is 80m.

The average score for the students in the afternoon class was 86, then the sum of their scores is 86n.

The sum of the scores of both classes is

80m+86n

and the average score is

\dfrac{80m+86n}{m+n}

The average (arithmetic mean) score for the two classes combined was 84, then

\dfrac{80m+86n}{m+n}=84\\ \\ 80m+86n=84m+84n\\ \\86n-84n=84m-80m\\ \\2n=4m\\ \\n=2m

This means n is greater, so afternoon class has more students.

7 0
3 years ago
A theatre group sold a total of 440 tickets for a show, making a total of $3940. Each regular ticket cost $5, each premium ticke
valentina_108 [34]

Answer: 330 regular tickets, 46 premium tickets and 64 elite tickets were sold.

Step-by-step explanation:

Let x represent the number of regular tickets that were sold.

Let y represent the number of premium tickets that were sold.

Let z represent the number of elite tickets that were sold.

The theatre group sold a total of 440 tickets for the show. It means that

x + y + z = 440- - - - - - - - - -1

Each regular ticket cost $5, each premium ticket cost $15, and each elite ticket cost $25. The total amount made from the show was $3940. It means that

5x + 15y + 25z = 3940- - - - - - - - - 2

The number of regular tickets was three times the number of premium and elite tickets combined. It means that

x = 3(y + z)

x = 3y + 3z

Substituting x = 3y + 3z into equation 1 and equation 2, it becomes

3y + 3z + y + z = 440

4y + 4z = 440- - - - - - - - - - - - -3

5(3y + 3z) + 15y + 25z = 3940

15y + 15z + 15y + 25z = 3940

30y + 40z = 3940 - - - - - - - - - - 4

Multiplying equation 3 by 10 and equation 4 by 1, it becomes

40y + 40z = 4400

30y + 40z = 3940

Subtracting, it becomes

10y = 460

y = 460/10

y = 46

Substituting y = 46 into equation 3, it becomes

4 × 46 + 4z = 440

184 + 4z = 440

4z = 440 - 184

4z = 256

z = 256/4

z = 64

x = 3(y + z) = 3(46 + 64)

x = 330

4 0
3 years ago
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