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1 year ago

What is the value of x in the equation below?

Mathematics

2 answers:

Rus_ich [418]1 year ago

7 0

Answer:

x= -12

Step-by-step explanation:

-2.5(x-4)=-3x+4

-2.5x+10=-3x+4

-2.5x+3x=-10+4

0.5x=-6

Divide by 0.5x/0.5 you cancel these two numbers.

-6/0.5 = -12

x= -12

I hope it helps. Let me know.

Nutka1998 [239]1 year ago

4 0

Answer:

B) x = -12

Step-by-step explanation:

[Given] -2.5(x-4) = -3x + 4

[Distibute] -2.5x + 10 = -3x + 4

[Subtract 4 from both sides] -2.5x + 6 = -3x

[Add 2.5x to both sides] 6 = -0.5x

[Divide both sides by -0.5] -12 = x

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

leave a comment if i am wrong

7 0

3 years ago

PLS HELP ASAP !!!!!!!!!!!

NemiM [27]

Answer:

with what?

Step-by-step explanation:

5 0

2 years ago

A random sample of 20 UF students is taken to test UFs claim that 54% of the student population are female.

baherus [9]

You didn't give the multiple choice so no one can help you do make sure to include that next time

8 0

2 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

2 years ago

Solve 1 And 2 Step Equations.

masha68 [24]

Answer:

ksbdksvudkdbckx skxid SORRRYYYYY BUT I NEED POINTSSSSS :(

7 0

2 years ago