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asambeis [7]
4 years ago
9

What is 7rad5 exapanded

Mathematics
2 answers:
soldier1979 [14.2K]4 years ago
7 0
5[3√2 - 7√5] / [(3√2 + 7√5)(3√2 - 7√5)] 
<span>5[3√2 - 7√5] / [9*2 - 49*5] </span>
<span>5[3√2 - 7√5] / [18 - 245] </span>
<span>5[3√2 - 7√5] / -227 OR </span>
<span>(15√2 - 35√5) / -227 </span>
frez [133]4 years ago
4 0
If you mean in decimal form then it would be 15.65
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3 years ago
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\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad  \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a,  k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases}\\\\ -------------------------------


\bf \cfrac{(x-5)^2}{144}-\cfrac{(y-4)^2}{81}=1\implies \cfrac{(x-5)^2}{12^2}-\cfrac{(y-4)^2}{9^2}=1 \\\\\\ \begin{cases} h=5\\ k=4\\ a=12\\ b=9 \end{cases}\implies c=\sqrt{144+81}\implies c=\sqrt{225}\implies c=15 \\\\\\ \stackrel{center}{(5,4)}\qquad \qquad \stackrel{\textit{because is a horizontal traverse hyperbola}}{\stackrel{foci}{\stackrel{(5\pm 15,4)}{(20,4),(-10,4)}}\qquad \qquad \stackrel{vertices}{\stackrel{(5\pm 12,4)}{(17,4),(-7,4)}}}

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