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natima [27]
3 years ago
15

Find the sum of the first 30 terms of the sequence below. an=4n+1

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer:  The sum of first 30 terms of the given sequence is 1890.

Step-by-step explanation:  We are given to find the sum of first 30 terms of the following sequence :

a_n=4n+1.

The first few terms of the above sequence are

a_1=5,\\\\a_2=9,\\\\a_3=13,\\\\a_4=17,\\\\a_5=21\\\\\vdots~~~~~\vdots~~~~~\vdots\\\\

So, the given sequence is an arithmetic one with first term 5 and common difference

d = 9 - 5 = 13 - 9 = 17 - 13 =  .  .  .  = 4.

Therefore, the sum of first 30 terms will be

S_{30}\\\\\\=\dfrac{30}{2}\{2a_1+(30-1)d\}\\\\\\=15(2\times5+29\times4)\\\\=15(10+116)\\\\=15\times 126\\\\=1890.

Thus, the sum of first 30 terms of the given sequence is 1890.

dmitriy555 [2]3 years ago
6 0
That would be 1,890.
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