Answer : (8,5)
Given
K(x) = ![8-\sqrt[3]{x}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7Bx%7D)
Now we plug in each point and check whether it satisfies our equation
(-64,12)
K(-64) =
= 12 so this point lie on graph
(125,3)
K(125) =
= 3 so this point lie on graph
(343,1)
K(343) =
= 1 so this point lie on graph
(8,5)
K(8) =
= 6 so this point does not lie on graph because we got 6 instead of 5
1) C. <u>19.4
</u>1/3(3)^3 + 5.2(2)
1/3(27) + 10.4
9 + 10.4
= 19.4
2) C. <u>6
</u>9 - (1/2)^4 * 48
9 - 0.0625 * 48
9 - 3
= 6
3) A. <u>2 times y divided by 7</u>
4) C. <u>5p - 4</u>
5) C. <u>Step 2; 4(2) + 4(4x)
</u>Hope this helps!<u>
</u>
Answer:
5x-6y-12=0
Step-by-step explanation:
...make y the subject y=-6/5x +2
...use the coefficient of x as the gradient,m=-6/5
...for a perpendicular line,find the negative reciprocal of the gradient,5/6
...sub into the eqn y= -1/m(x-a)+b
Answer:
I am
Step-by-step explanation:
1500