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AnnZ [28]
4 years ago
14

Find the product x^3(x^2+5x+1)

Mathematics
2 answers:
lord [1]4 years ago
5 0

By the distributive law,

x^3(x^2+5x+1) = x^5 + 5x^4 + x^3


OLEGan [10]4 years ago
3 0
Hope This helps !!!!

You might be interested in
(q+4)(9q+5)=0 solve for q
mariarad [96]

Answer:

q = -4
q = -5/9

Step-by-step explanation:

Hi!

To solve this question, we can use the zero product property.

<h2>What is the Zero-Product property?</h2>

The zero product property states that if one factor is equal to 0, then the whol equation is equal to 0.

We have (q+4)(9q +5) = 0

That means either q + 4 = 0, or 9q + 5 = 0.

Solve:

  • q + 4 = 0
  • q = -4

  • 9q + 5 = 0
  • 9q = -5
  • q = -5/9

We can check both cases:

(-4 + 4)(-36 + 5) = 0

0(-31) = 0

0 = 0

(-9/5 + 4)(9(-5/9) + 5) = 0

(2.2)(-5 + 5) = 0

(2.2)0 = 0

0 = 0

5 0
3 years ago
Write down the value of the 6 in the number 2693​
Goshia [24]

Answer:

6 = 600

Step-by-step explanation:

in a decimal number the digits to the left of the decimal point represent a whole number

4 0
3 years ago
Read 2 more answers
460 <br><br> Wrote this in word form and expanded form?
zepelin [54]

Answer:460 in word form: Four Hundred Sixty

460 in expanded form: 400+60

4 0
4 years ago
The product of eight and a number decreased by four is the same as eight plus five time the same number.
dedylja [7]

Answer:

The Answer is: The Number is 4

Step-by-step explanation:

Let n = the number.

Eight times a number minus 4 equals 8 plus 5 times the number.

8n - 4 = 8 + 5n

3n = 12

n = 4, the number is 4.

Proof:

8(4) - 4 = 8 + 5(4)

32 - 4 = 8 + 20

28 = 28

Hope this helps! Have an Awesome Day!! :-)

5 0
4 years ago
Please help! The radius of a sphere is claimed to be 3.0 inches, correct to within 0.01 inch. Use linear approximation to estima
Vilka [71]

Answer:

0,36π inches³ or simply 1.13 inches³

Step-by-step explanation:

In this case, first, we need to calculate the volume of the sphere with the formula:

V = 4πr³/3

Replacing the data we have:

V = 4π(3)³/3

V = 36 in³

Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:

If V = 4πr³/3

Then the derivate of V (dV) would be:

dV = 4π*3*r²/3 dr

Where dr is the error of radius so:

dV = 4π*r² dr

Solving for dV:

dV = 4*3.14*(3)²*(0.01)

dV = 1.13 in³

So at the end, we just report the volume of the sphere as

V = 36 ± 1 in³

dV =

3 0
3 years ago
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