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Korolek [52]
2 years ago
5

Choose 5 different organisms. At least one of your organisms needs to be a plant. List an adaptation and describe how the adapta

tion is helpful for each organism you choose
Biology
1 answer:
spayn [35]2 years ago
6 0

Answer:

1) wood frog - freezes their body in winter

To survive the winter Wood Frogs' bodies freeze solid. They also stop breathing and their heart stops beating. This allows them to survive temperatures as low as -80 degrees Fahrenheit. And in spring, they thaw out and "come back to life.

2) Kangaroo rats survive without ever drinking water.

Kangaroo rats have adapted to survive in the desert without ever taking a sip of water. Instead, they get all the moisture they need from the seeds that they eat. These critters also have incredible hearing and can jump up to nine feet, which helps them avoid predators.

3) Chameleon - blend in with the environment by changing its color to escape from predators

4)Okapi have scent-glands on their feet.

Okapi are strange animals that look like a combination of a giraffe and a zebra. They live in the Democratic Republic of Congo, where it's very hot and predators, such as leopards, are always lurking. To stay alive, okapi have a three key adaptations. First, they have scent-glands on their feet to mark their territory. Second, they have infrasonic calls, which allows them to communicate with their calves without predators hearing their call. Finally, they have 14-18 inch-long tongues, which can be used to wash their eyes and ears.

5)Venus fly trap plant that is adapted for living in soil that doesn't provide enough nutrients.

6)  the seaweed is a plant adapted for its underwater environment

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This tutorial will take you step by step through the question. Individuals with the genotypes Aa Bb CC Dd and Aa bb Cc Dd are cr
Mrac [35]

Answer:

The correct answer is -

a) 1/16

b) 1/64

c) 1/32

Explanation:

According to the law of independent assortment, each allele of a particular gene has equal chances of getting inherited into the gametes.

In a Mendelian cross of Aa x Aa would give;

AA = 1/4,

Aa = 2/4 and

aa = 1/4

The result of the cross between AaBb x AaBb would be 1/16 due to the fact that probability is still the same AA = 1/4, BB = 1/4 therefore, AABB = 1/16 = 1/4× 1/4.

Now based on this crossing the following:

AaBbCCDd x AabbCcDd.

Take each allele as individual

Aa x Aa would give; AA = 1/4, Aa = 2/4 and aa = 1/4

Bb x bb would give; BB = 1/2, bb = 1/2

CC x Cc would give; CC = 1/2, Cc = 1/2

Dd x Dd would give; DD = 1/4, Dd = 2/4 and dd = 1/4

Then the probability of progeny of the following would be:

a) the probability of AaBbCcDd = 2/4 x 1/2 x 1/2 x 2/4 = 1/16

b) the probability of aabbCCdd = 1/4 x 1/2 x 1/2 x 1/4 = 1/64

c) the probability of AabbCcDD = 2/4 x 1/2 x 1/2 x 1/4 = 1/32

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Vinil7 [7]
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