30/5 = 6
30 - 6 = 24
Therefore, only 24 students were in class today.
Answer:
Standardized z score = 2.06
His house rent is not an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard university is 970 with a standard deviation of 204. John`s rent is 1390. What is his standardized z-score? Is john`s rent an outlier? How high would the rent have to be to qualify as an outlier
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score = 1390
μ is the population mean = 970
σ is the population standard deviation = 204
His z score is calculated as:
z = 1390 - 970/204
z = 2.06
No his house rent is not an outlier
Hello :
tanA = sinA/cosA
cosA = sinA /tanA
cosA =(4/5)/(4/3)
cosA=3/5
Answer:
Step-by-step explanation:
This is a system of inequalities problem. We first need to determine the expression for each phone plan.
Plan A charges $15 whether you use any minutes of long distance or not; if you use long distance you're paying $.09 per minute. The expression for that plan is
.09x + 15
Plan B charges $12 whether you use any minutes of long distance or not; if you use long distance you're paying $.15 per minute. The expression for that plan is
.15x + 12
We are asked to determine how many minutes of long distance calls in a month, x, that make plan A the better deal (meaning costs less). If we want plan A to cost less than plan B, the inequality looks like this:
.09x + 15 < .15x + 12 and "solve" for x:
3 < .06x so
50 < x or x > 50
For plan A to be the better plan, you need to talk at least 50 minutes long distance per month. Any number of minutes less than 50 makes plan B the cheaper one.
