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2 years ago

Plz help me I’m so confused about this stuff

Mathematics

1 answer:

son4ous [18]2 years ago

6 0

Answer: 19

Step-by-step explanation: all you do is plug in 3 in the equation so like this 2(3) ^2 +1

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Esteban is making turtle brownies. the recipe calls for 3/4 bag of caramel squares. one bag has 24 caramel squares in it.

frez [133]

I believe the answer is 18

5 0

3 years ago

Read 2 more answers

Y = 8x + 6, x = 5 plz help i can get admin if i solve this

RoseWind [281]

Answer:

y = 46

Step-by-step explanation:

I'm assuming you wanted to solve for y.

x = 5

y = 8(5) + 6

y = 40 +6

y = 46

8 0

3 years ago

A square notepad has sides that are 10 centimeters long. What is the notepad's area?

blsea [12.9K]

Answer:

100cm²

Step-by-step explanation:

The notepad is square.

The area of a square = length X width.

All the sides of a square are the same length.

Therefore, the area of the notepad = 10 X 10 which equals 100.

Don't forget the units!

The units for area is cm².

The units for volume is cm³.

This is area so your answer is 100cm².

Hope this helped, have a nice day!

8 0

1 year ago

What is the solution set for -3x<15?

antoniya [11.8K]

The soultion for the set is the second one

3 0

3 years ago

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago