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3 years ago

If four points are collinear, they are also coplanar. O A. True B. False

Mathematics

1 answer:

dimaraw [331]3 years ago

6 0

True because I don’t actually know I just need points

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What is the maximum value of P = 4x + 2y, given the constraints on x and y listed below?

Solnce55 [7]

P = 4x + 2y

additional info.
x+2y < 10
y < 2
x > 0
y > 0

y can only be 0, 1, and 2.

x + 2(0) < 10 = x < 10
x + 2(1) < 10 = x + 3 < 10 = x < 10 - 3 = x < 7
x + 2(2) < 10 = x + 4 < 10 = x < 10 - 4 = x < 6

x = 10 ; y = 0 : P = 4(10) + 2(0) = 40 + 0 = 40
x = 7 ; y = 1 : P = 4(7) + 2(1) = 28 + 2 = 30
x = 6 ; y = 2 : P = 4(6) + 2(2) = 24 + 4 = 28

The maximum value of P is 40. Where x is 10 and y is 0.

5 0

4 years ago

Read 2 more answers

Can show me how to do this ?

elena-s [515]

You have to multiply your 20cm by 6cm and your final answer being 120 because 0 times 6 is zero and 2 times 6 is 12, then that getting you 120

4 0

3 years ago

Which expression represents the average of three test scores?

fomenos

Answer:

It is C

Step-by-step explanation:

trust me ☜(ﾟヮﾟ☜)

4 0

3 years ago

Read 2 more answers

One number is 1/2 of another number the sum of the two numbers is 27 find the two numbers

Art [367]

Filling up the space because it has to be 20 characters

4 0

3 years ago

The Wall Street Journal reported that automobile crashes cost the United States $162 billion annually (2008 data). The average c

ivanzaharov [21]

Answer:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

8 0

3 years ago