Answer:
Change 45 min to .75 hrs
Distance = speed * time
Train A's distance = 55(t+.75)
Train B's distance = 70t
The equation
D(t) = 70t + 55(t+.75)
x^0 + y^0
3^0 + 2^0
1 + 1 =2
your answer : 2
<u>Hint any number with the power of zero is 1</u>
Hope i helped!!! :)
Answer:
1) Distribute 1.2 to 6.3 and -7x
2)Combine 3.5 and 7.56
3)Subtract 11.06 from both sides
Step-by-step explanation:
3.5 + 1.2(6.3 - 7x) = 9.38
Distribute 1.2 to 6.3 and -7x
3.5 + 1.2* 6.3 - 1.2 * 7x = 9.38
3.5 + 7.56 - 8.4x = 9.38
Combine 3.5 and 7.56
11.06 - 8.4x = 9.38
Subtract 11.06 from both sides
11.06 - 8.4x -11.06 = 9.38 - 11.06
-8.4x = -1.68
To find solution:
Divide both sides by (-8.4)
-8.4x/-8.4 = -1.68/-8.4
x = 0.02
This translates to "a number" is greater than 45. All you have to do now is translate these words into an algebraic statement. Basically, you replace "a number" with the variable which it is defined for, and you use the "greater than" symbol to show that the variable is greater than the value of 45.
Only use this one pls. Lol
