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pogonyaev
3 years ago
12

Part A) Julio makes a scale drawing of the kitchen floor to determine how many square feet of flooring he needs to buy . The sca

le of his drawing is 1 inch:4 feet. (The length is 4 1/2 and the width is 3 3/8)
What is the actual are of Julio's kitchen floor?

Part B) Julio makes a scale drawing of part of the kitchen wall to design a tile pattern. He will use gray tiles and white tiles to form the pattern shown. The length of each square in the drawing represents 1/2 foot on the actual kitchen wall. (There are 14 gray tiles and 10 white tiles)

If Julio uses 2-inch by 2-inch tiles, how many tiles of each color will he need?
Mathematics
2 answers:
serg [7]3 years ago
6 0
Part A) 
we know that
<span>scale ---------->  inch/4 feet=0.25 in/ft

</span>[scale]=[scale drawing]/[actual]
[actual]=[scale drawing]/[scale]

for <span>length --------> 4 1/2 in ---------> 4.5 in  (</span>scale drawing)
[actual]=[4.5]/[0.25]=18 ft

for <span>width ---------> 3 3/8 in</span> ---> (3*8+3)/8 ---> 27/8 in  (scale drawing)
[actual]=[27/8]/[0.25]=13.5 ft

the answer part A is
length actual <span>kitchen floor is 18 ft
</span>width actual kitchen floor is 13.5 ft

Part B)  
the area of one square in the actual=(1/2)*(1/2)=0.25 ft²
total area gray tiles=0.25*14=3.5 ft²
total area white tiles=0.25*10=2.5 ft²

find <span>how many tiles 2 in by 2 in of each color will he need
1ft</span>²-------------> 144 in²
gray tiles
3.5 ft²---------------> 3.5*144=504 in²
[tiles 2 in by 2 in gray]=504/(2*2)=126 gray tiles 

white tiles
2.5 ft²---------------> 2.5*144=360 in²
[tiles 2 in by 2 in white]=360/(2*2)=90 white tiles 

the answer Part B) is
126 gray tiles
90 white tiles 



Kitty [74]3 years ago
5 0

Answer:

Sample response: Julio divided 6 whole parts into groups of 2 instead of dividing them into groups of  

1

2

which would make the quotient 12, not 3.

Step-by-step explanation:

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A rectangular storage container with an open top is to have a volume of 24 cubic meters. The length of its base is twice the wid
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Answer:

419.25

Step-by-step explanation:

The calculation of the cost of materials for the cheapest such container is shown below:-

We assume

Width = x

Length = 2x

Height = h

where, length = 2 \times width

Base area = lb

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Side area = 2lh + 2bh

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= 4xh + 2xh

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= 13(2x^2) + 9(4xh + 2xh)\\\\ = 13(2x^2) + 9(4x + 2x)\times \frac{12}{x^2} \\\\ = 26x^2 + \frac{648}{x}

now we have to minimize C(x)

So, we need to compute the C'(x)

= 52x - \frac{648}{x^2}

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= 52x - \frac{648}{x^2} = 0\\\\ x = \frac{648}{52}^{\frac{1}{3}}

C" = ((\frac{648}{52} ^{\frac{1}{3} } = 52 + \frac{1296}{(\frac{648}{52})^\frac{1}{3} )^3}\\\\ = 52 + \frac{1296}{\frac{648}{52} } >0

So, x is a point of minima that is

= (\frac{648}{52} )^\frac{1}{3}

Now, Base material cost is

= 13(2x^2)\\\\ = 26(\frac{648}{52} )^\frac{2}{3}

= 139.75

Side material cost is

= \frac{648}{x} \\\\ = \frac{648}{(\frac{648}{52})^\frac{1}{3}  }

= 279.50

and finally

Total cost is

= 139.75 + 279.50

= 419.25

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