Answer:
The answer to your question is (2)(3)(11)
Step-by-step explanation:
Data
154
Process
1.- Find the prime factors of 154, starting with 2, then, 3, 5, 7, etc
154 2
77 7
11 11
1
2.- Write 154 as a composition of prime factors
154 = (2)(7)(11)
3.- Conclusion
The prime factors of 154 are 2, 3 and 11
Answer:

Step-by-step explanation:


The answer is: z² .
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Given: <span>(x÷(y÷z))÷((x÷y)÷z) ; without any specified values for the variables;
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we shall simplify.
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We have:
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</span>(x÷(y÷z)) / ((x÷y)÷z) .
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Start with the first term; or, "numerator": (x÷(y÷z)) ;
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x ÷ (y / z) = (x / 1) * (z / y) = (x * z) / (1 *y) = [(xz) / y ]
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Then, take the second term; or "denominator":
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((x ÷ y) ÷z ) = (x / y) / z = (x / y) * (1 / z) = (x *1) / (y *z) = [x / (zy)]
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So (x÷(y÷z)) / ((x÷y)÷z) = (x÷(y÷z)) ÷ ((x÷y)÷z) =
[(xz) / y ] ÷ [x / (zy)] = [(xz) / y ] / [x / (zy)] =
[(xz) / y ] * [(zy) / x] ;
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The 2 (two) z's "cancel out" to "1" ; and
The 2 (two) y's = "cancel out" to "1" ;
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And we are left with: z * z = z² . The answer is: z² .
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Answer:
82
Step-by-step explanation:
because 63% of 130 is 81.9
and since the question is asking approximately which means rounding, so you round 81.9 to get 82.
Answer:

Step-by-step explanation:
