Here you have 2 linear equations and are to solve this system. Both equations have already been solved for y, so you can set one of them = to the other one:
-2x+11 = -3x+21.
Then 3x-2x = 21 - 11, or x = 10 (answer)
Find y by subst. x = 10 into either of the given equations.
Solution is then (10, ? )
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.
Step-by-step explanation:
f (x) =y
y=x^4 -3x + x^2
incomplete
Answer:
16
Step-by-step explanation:
solution,
2a-4b
2*2-4*-3
4-(-12)
4+12
16