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Lapatulllka [165]
3 years ago
13

Which is the principal value of arctan (3.7)? PLEASE HELPP CANT GET IT WRONG

Mathematics
1 answer:
NeTakaya3 years ago
6 0

Answer:

1.42π rad

Step-by-step explanation:

Principal value are known to be the largest value that can be equivalent to the trigonometry expression given.

Given

θ = arctan (3.7)

θ = 74.9°

The principal value of the angle can be found in the 3rd quadrant.

In the third quadrant, the angle gotten will become 180° + 74.9°

= 254.9°

Converting to radians

Since πrad = 180°

x = 254.9°

180x = 254.9π

x = 254.9π/180

x = 1.42π rad

The principal value of the angle is 1.42π rad.

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Answer:

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Step-by-step explanation:

18-0.01=17.99

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Identify the conic section represented by the equation:<br> x2 + 2x + 2y2 – 12y + 11 = 0<br> 2
wlad13 [49]

Answer:

Equation of the Ellipse

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the equation

                 x² + 2 x + 2y² - 12 y +11 = 0

      ⇒       x² + 2 x + 1 - 1 + 2(y² - 6 y )+ 11 = 0

                 x² + 2 x + 1 - 1 + 2(y² - 2(3) y+9-9 )+ 11 = 0

     ⇒        x² + 2 x + 1 - 1 + 2(y² - 2(3 y ) +  3²- 3² ) + 11 = 0

By using (a +b)² = a² + 2 a b + b²

               (a -b)² = a² - 2 a b + b²

<u><em>Step(ii):-</em></u>

          x² + 2 x + 1 - 1 + 2(y² - 2(3 y ) +  3²- 3² ) + 11 = 0

    ⇒  ( x+1)² +2( y-3 )² - 1 - 2(9) +11 =0

   ⇒   ( x+1)² +2( y-3 )² - 8 =0

           ( x+1)² +2( y-3 )² = 8

Dividing '8' on both sides , we get

         \frac{(x+1)^{2} }{8} + \frac{2(y-3)^{2} }{8} = 1

      \frac{(x+1)^{2} }{8} + \frac{(y-3)^{2} }{4} = 1

This equation represents the Ellipse

 

3 0
3 years ago
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Step-by-step explanation:

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Answer:

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