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Semmy [17]
3 years ago
5

write a equation for the vertical and horizonal lines passing through the points (4,1) I know x=4 and y=1 but what eles do I do?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
Well you solve the equation then find out what you dealing with
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Select all the values that are equivalent to the given expression. Express your answer in scientific notation.
Anna35 [415]

Answer:

the first and last ones

Step-by-step explanation:

5 0
3 years ago
The national average for the math portion of the College Board’s Scholastic Aptitude Test
Alex73 [517]

Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(score greater than 615)

P(x > 615)

P( x > 615) = P( z > \displaystyle\frac{615 - 515}{100}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%

b) b) P(score greater than 715)

P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%

c) P(score between 415 and 515)

P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%

P(415 \leq x \leq 515) = 34.1\%

d) P(score between 315 and 615)

P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%

P(315 \leq x \leq 615) = 81.8\%

4 0
4 years ago
BRAINLIST TO THE FIRST PERSON THAT GETS THIS RIGHT!!!!Decide whether this inequality statement is true or false. -5 &gt; 2 *
Maksim231197 [3]

Answer:

400x(400×x) i think

3 0
3 years ago
Round 7.2352297363 to nearest millionth
Elodia [21]

Answer:

7.23522974

Step-by-step explanation

7 would be in the ones place, 2 in the tenths, 3 in the hundredth, 5 in the thousandth, and so on. Since the number after 3 is over 5, it will go up by one. So the answer would be 7.23522974

6 0
3 years ago
Read 2 more answers
You and three friends decide to go to the fair. The cost for parking is three dollars. Admission is 12 dollars per person. If yo
nika2105 [10]
Let the variable f represent the amount of money that each person can spend on food.

We shall start by placing the total amount of dollars you have on the left side of the inequality.  This has to be less than or equal to the number of dollars that you and your group of friends spends, because you can't spend more money than you have ;) 

Also, on the right side of the inequality, we know that you and your friends spend 3 dollars, because that is how much parking costs.  In addition to this, we have admission, which costs 12 dollars per person, and there are 4 people in your group. 12*4=48, which is the total cost of admission for your group.  Finally, you need to add the cost of food to this side of the inequality, which is the same for each person in your 4 person group.  This can be represented by the expression 4f.

So, if we write this inequality, it would be:

155≤ 3 + 48 + 4f

If we simplify the right side of the inequality, by combining like terms, we get the simplified inequality:
155 ≤ 51 + 4f

To further simplify this inequality, we must keep all of the integers on the left side, in attempt to get the variable alone on the right side.  To do this, we must subtract 51 from both sides of the inequality, to get:

104 ≤ 4f

Finally, we must divide both sides of the inequality by 4, because it is the coefficient of f, and that is the variable that we are trying to get alone.

26 ≤ f

This means that you and each of your friends can only spend 26 dollars each on food.
3 0
3 years ago
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