Answer:
63
Step-by-step explanation:
64+53+ (ㅣ) = 180
117 + (ㅣ) = 180
(ㅣ) = 63
Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes
1sr event: drawing an I ( there are 2 I); P(1st I) = 2/11
2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)
2nd event : P(also one I) = 1/10
P(selecting one I AND another I) is 2/11 x 1/10
P(selecting one I AND another I) =2/110 = 0.018
9514 1404 393
Answer:
22
Step-by-step explanation:
The average of the 6 even integers is the odd integer halfway between the first three and the last three. That average value is 126/6 = 21, so the 4th integer is 21+1 = 22.
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All 6 are {16, 18, 20, 22, 24, 26}.
